[klee-dev] Need help in understanding a kquery generated by KLEE
Cristian Cadar
c.cadar at imperial.ac.uk
Thu Jun 16 21:54:38 BST 2022
Hi Sandip,
Those constants are most likely derived from concrete addresses, but you
should try to simplify the program as much as possible and send a full
program that can be compiled and run.
Best,
Cristian
On 02/05/2022 19:22, Sandip Ghosal wrote:
> Hello,
>
> I need help in understanding a kquery file generated by KLEE.
>
> Consider the following C program:
>
> void* foo(struct node *item1. struct node *item2){
> if(item1 == item2){
> item1->next = NULL;
> }
> return item1;
> }
>
> void main(){
> struct list *array[3];
> // next allocate memory for each array[I], i=0,1,2
> int item1 = klee_range(0, 3, "item1");
> int item2 = klee_range(0, 3, "item2");
> foo(array[item1], array[item2]);
> }
>
> Since my main objective is to understand the query, the above program is
> simplified and loosely written for reference. Now KLEE generates one
> kquery as follows:
>
> array const_arr1[24] : w32 -> w8 = [32 77 0 133 168 85 0 0 240 68 0 133
> 168 85 0 0 0 77 0 133 168 85 0 0]
> array item1[4] : w32 -> w8 = symbolic
> array item2[4] : w32 -> w8 = symbolic
>
> (query [(Ult N0:(ReadLSB w32 0 item1)
> 3)
>
> (Ult N1:(ReadLSB w32 0 item2)
> 3)
>
> (Eq N2:(ReadLSB w64 N3:(Extract w32 0 (Mul w64 8 (SExt w64
> N0))) const_arr1)
> (ReadLSB w64 N4:(Extract w32 0 (Mul w64 8 (SExt w64 N1)))
> const_arr1))
>
> (Eq false
> (Ult (Add w64 18446649891435295456 N2) 9))
>
> (Ult (Add w64 18446649891435295488 N2) 9)]
> false)
>
> I am struggling to understand the second and third last line of the
> query which seems to be performing a boundary check on a flat byte
> memory address. I understand KLEE is implicitly branching over the
> statement item1->next = NULL, 18446649891435295456 perhaps is the base
> address for item1, and N2 computes the offset. However, I am failing to
> understand how the base address is computed and why it is always
> compared with a constant value of 9?
>
> Thanks in advance.
>
> --
> Thanks & Regards
> Sandip Ghosal
>
>
>
>
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