XSL patterns give me a node--how can I find it's position?

Richard Anderson rja at arpsolutions.demon.co.uk
Thu Nov 11 18:31:24 GMT 1999

Forgeting the nodes collections (because it is an overhead getting that
anyway), once you've got the node your interested
it, simply do something like this:

' Grab the node via an XSL pattern

dim iCount as integer
set node = dom.selectNodes( "whatever XML pattern" )
iCount = 0

' While this node is not the first chlid node

while not (node.prevSibling is nothing) then

    ' Add one to count and move back

    iCount = iCount + 1
    set node = node.prevSibling


Basically you just count until there is nobody to your left, then the count
should give you the index you need.



DEV-XML - THE *new* Windows/MSXML Developer Maiing List - To join send a
email to dev-xml-subscribe at onelist.com

xml-dev: A list for W3C XML Developers. To post, mailto:xml-dev at ic.ac.uk
Archived as: http://www.lists.ic.ac.uk/hypermail/xml-dev/ and on CD-ROM/ISBN 981-02-3594-1
To unsubscribe, mailto:majordomo at ic.ac.uk the following message;
unsubscribe xml-dev
To subscribe to the digests, mailto:majordomo at ic.ac.uk the following message;
subscribe xml-dev-digest
List coordinator, Henry Rzepa (mailto:rzepa at ic.ac.uk)

More information about the Xml-dev mailing list