If SAX == lex, then what == yacc?

[James Tauber]

> [Ron Daniel]  A tool that took a DTD and generated a SAX
> DocumentHandler for parsing instances that are to conform
> to the DTD. (This much is not too hard to do for basic element
> and attribute declarations.)
>
> The next step would be to add the equivalent
> of yacc actions (e.g.  $$ = $1 + $2  if my memory of yacc
> serves) to the DTD so that in addition to validating the
> instance you can store it into a desired structure, perform
> arbitrary calculations, etc.

Right. This is pretty much what I've started doing with FOP. I have a
schema-like document with additional calculations in it.

James


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